1.

K_(sp) for Cr(OH)_(3) is 2.7 xx 10^(-31). What is its solubility in moles/litre

Answer»

`1 XX 10^(-8)`
`8 xx 10^(-8)`
`1.1 xx 10^(-8)`
`0.18 xx 10^(-8)`

SOLUTION :`{:(Cr(OH)_(3),rarr,Cr^(+3)+,3OH^(-)),(,,x,3x):}`
`K_(sp) = x.(3x)^(3) = 27 x^(4)`
`x = 4sqrt((K_(sp))/(27)) , x = 4sqrt((2.7 xx 10^(-31))/(27))`
`x = 1 xx 10^(-8)` mole/litre.


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