1.

K_(sp) for sodium chloride is 36 mol^(2)//"litre"^(2). The solubility of sodium chloride is

Answer»

`(1)/(36)`
`(1)/(6)`
6
3600

Solution :`{:(NaCl,hArr,NA^(+),+,Cl^(-)),(,,S,,S):}`
`K_(sp) = S^(2), S = sqrt(K_(sp)) = sqrt(36) = 6`.


Discussion

No Comment Found