1.

Ka for H_(3)BO_(3) "is" 5.8xx10^(-10) what buffer component ratio [NaH_(2)BO_(3)(aq.)]//[H_(3)BO_(3)(aq.)] would be needed to make a buffer solution of pH=10.

Answer»

10
0.18
4.3
5.8

Solution :`pH=pKa+log.([NaH_(2)BO_(3)])/([H_(3)BO_(3)])`
`[H^(+)]=Kaxx([H_(3)BO_(3)])/([NaH_(2)BO_(3)])`
`10^(-10)=5.8xx10^(-10)XX([H_(3)BO_(3)])/([NaH_(2)BO_(3)])`


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