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कैलकुलेट थे एरिया ऑफ़ थे शेडेड रेगिनीं एच ऑफ़ थे फिगुरेसगिवें बिलो |
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Answer» Shaded Area=Area of RECTANGLE AGJF+ Area of rectangle HCDI+ Area of semi circular ring ABCHG+ Area of SEMICIRCULAR ring DEFJIArea of rectangle AGJF=25×3.4=85m 2 .Area of rectangle HCDI=25 3.4=85m 2 .Area of a ring ABCHG=[(R 2 −r 2 )]= 722 [(9.55) 2 −(6.15) 2 ]Area of ring DEFJI=π[(R 2 −r 2 )]= 722 [(9.22) 2 −(6.15) 2 ]=(25×3.4)+(25×3.4)+ π[(9.55) 2 −(6.15) 2 ]+ 21 π[(9.55) 2 −(6.15) 2 ]=[85+85+ 722×15.7×3.4]m 2=(170+167.77)m 2=337.77m 2 |
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