1.

KBr contains 32,9 % potassium by mass. If 6.40 g of Br_(2) is made to react with 3.60 g of potassium, the actual mass of potassium which reacted with Br_(2) is

Answer»

3.14 g
1.76 g
3.6 g
None of these

Solution :% of BROMINE in KBR `= 100-32.9=67.1%`
67.1 g of bromin react with potassium = 32.9 g
6.40 g of bromine react with potassium
`=((32.9)XX(6.40g))/((67.2g)) = 3.138 g = 3.14 g`


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