1.

KBr is 80% dissociated in aqueous solution of 0.5 m concentration (Given K_(f)=1.86 " K kg" mol^(-1)). The solution freezes at :

Answer»

271.326 K
272 K
270.5 K
268.5 K.

Solution :`ALPHA=(i-1)/(n-1)or 0.8=(i-1)/(2-1)
i=1.28, DeltaT_(F)=iK_(f)m`
` =1.28xx(1.86 K KG mol^(-1))xx(0.5 mol kg^(-1))`
=1.674 K.
f.p. of solution=(273-1.674) = 271.326 K


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