1.

KBr undergoes 80% dissociationin its 0.5M aqueoussolution.Calculatethe osmotic pressureof thissolutionat 287^(@)C.

Answer»

<BR>

Solution :KBR DISSOCIATES as
`KBr to K^(+) + Br^(-)`
If `alpha` is the degree of dissociation , then
`alpha= (i-1)/(m-1)`
m = 2 , `alpha = 80% = 0.80`
` 0.80 = (i-1)/(2-1)`
` i=1 = 0.80`
`i=0.80 + 1 = 1.80`
` pi = icRT`
` = 1.80 xx 0.5 xx 0.0821 xx300`
` = 22.167 ` ATM


Discussion

No Comment Found

Related InterviewSolutions