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Ketone (A), which indergoes halform reaction, give compound (B) on reduction. (B) on heating with H_(2)SO_(4) gives compound (C ), which forms mono-ozonide (D). (D) on hydrolysis in the presence of Zn dust gives only acetaldehyde. Identify (A). (B), and (C ). Write down the reactions involved. |
Answer» Solution :Ketone `(A)` gives HALOFORM reaction, so it must contain `(Me-CO-)` group. Ketone on reduction gives `2^(@)` alcohol. (B), which gives alkene `(C )` with `H_(2)SO_(4)`. Alkene on ozonolysis FOLLOWED by reduction with `Zn` dust gives `MeCHO`. So, the structure of alkene `(C )` is: So `(A)` is: Butan-`2`-one, `(B)` is: Butan-`2`-ol, `(C )` is: Butan-`2`-one. |
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