1.

KF has NaCl structure. The edge length of its unit cell has been found to be 537.6 pm. The distance between K^(+) and F^(-) in KF is :

Answer»

537.6pm
268.8pm
1075.2pm
cannot be calculated

Solution :In KF, edge LENGTH is equal to `2(r_(K^(+))+r_(F^(-)))` so that,
`r_(K^(+))+r_(F^(-))= ( 537)/( 2) = 268.8`PM


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