Saved Bookmarks
| 1. |
KI and surcose solution with 0.1 M concentration have osmotic pressure of 0.465 atm and0.245 atm respectively . Find the van't Hoff of KI and its degree of dissociation |
|
Answer» SOLUTION :For KI solution `pi` = I CRT ` 0.465 = I 0.1 xx R xx T ` For surcrose solution`pi` = CRT ` :. " " 0.245 = 0.1 xx R xx T ` Dividing (i) by (ii) , we GET ` I = (0.465)/(0.245) = 1.898 ` If `alpha`` {:("If "alpha" is he DEGREE of dissociation, ",KI,hArr,K^(+),+,I^(-)),("Initial","1 mole",,,,),("After disso.",1-alpha,,alpha,,alpha):}` Total moles after dissociation ` = (1-alpha) + alpha + alpha = 1 + alpha` `:. i = 1+alphaor alpha = i - 1 = 1.898 -1 =0.898 = 89.8 ` % |
|