1.

Kinetic energy of a charged particle decreases by 100 J when it is brought from a point of 100 V potential to a point of 200 V potential, then charge of particle is ...... C.

Answer»

`0.1`
`1.0`
10
100

Solution :According to law of CONSERVATION of energy KINETIC energy + potential energy (at one point) = kinetic energy + potential energy
`:. K_(1) +qV_(1)=K_(2)+qV_(2)`
`:. K_(1)-K_(2)= DELTAK =q (V_(2)-V_(1))`
`:. 100 = 100 q`
`:. Q = +1 C `


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