1.

KMnO_(4) can be prepared from K_(2)MnO_(4) as per the reaction, 3MnO_(4)^(2-)+2H_(2)O hArr 2MnO_(4)^(2-)+MnO_(2)+4OH^(-) The reaction can go to completion by removing OH^(-) ions by adding.

Answer»

KOH
`CO_(2)`
`SO_(2)`
`KCl`

Solution :HCl and `SO_(2)` are reducing AGENTS and can REDUCE `MnO_(4)^(-).CO_(2)` which is neither oxidising and nor reducing will provide only acidic medium. It can shift reaction in forward direction and reaction can go to COMPLETION.


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