1.

KMnO_(4) can be prepared from K_(2)MnO_(4)as per the reaction : 3MnO_(4)^(2-) + 2H_(2)O hArr2MnO_(4)^(-) + 4OH^(-) Thereaction can go to completion by removing OH^(-) ions by adding

Answer»

HCl
KOH
`CO_(2)`
`SO_(2)`

Solution :`3MnO_(4)^(2-) + 2H_(2)O hArr 2MnO_(4)^(-) + MnO_(2) + 4OH^(-)`
The reactioncan GOTO completion by removing `OH^(-)` ions by adding `CO_(2)` as it reacts with `OH^(-)` ion to form `CO_(3)^(2-)` ions
`4OH^(-) + 2CO_(2) rarr2CO_(3)^(2-) + 2H_(2)O`


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