1.

KMnO_(4)gets reduced to

Answer»

`K_(2)MnO_(4)` in neutral medium
`MnO_(2)` in acidicmedium
`MN^(2+)` in ALKALINE medium
`MnO_(2)` in neutralmedium

SOLUTION :`KMnO_(4)` is reduced to `MnO_(2)` in neutral medium
`2KMnO_(4) + H_(2)O rarr 2MnO_(2)+ 2KOH+3(O)`
or `MnO_(4)^(-) + 2H_(2)O+ 3E^(-) rarr MnO_(2) + 4OH^(-)`
In alkaline medium, it is reduced to `K_(2)MnO_(4)` or `MnO_(2)` . In acidic medium, it is reduced to `Mn^(2+)`


Discussion

No Comment Found