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KMnO_(4)gets reduced to |
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Answer» `K_(2)MnO_(4)` in neutral medium `2KMnO_(4) + H_(2)O rarr 2MnO_(2)+ 2KOH+3(O)` or `MnO_(4)^(-) + 2H_(2)O+ 3E^(-) rarr MnO_(2) + 4OH^(-)` In alkaline medium, it is reduced to `K_(2)MnO_(4)` or `MnO_(2)` . In acidic medium, it is reduced to `Mn^(2+)` |
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