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KMnO_(4) reacts with oxalic acid according to the equation 2MnO_(4)^(-)+5C_(2)O_(4)^(2-)+16H^(+) to 2Mn^(2+)+10CO_(2)+8H_(2)O Here, 20 mL of 0.1 M KMnO_(4) is equivalent to: |
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Answer» 120 ML of 0.25 M `H_(2)C_(2)O_(4)` |
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