1.

Kohlrausch's law helps to determine the degree of dissociation of a weak electrolyte at a given concentration.The molar conductivityLambda_mof .001M acetic acid is 4.95xx10^(_5)Scm^2mol^(-1).Calculate the degree of dissociation(alpha)at this concentration if limiting molar conductivitylamda_m^0for H+is 340xx10^(-5)Scm^2mol^(-1)and CH_3COO^-50.5xx10^(-5)Scm^2mol^(-1)

Answer»

SOLUTION :`lamda_m^0CHCOOH=4.95XX10^(-5)Scm^2mol^(-1)`
`lamda_m^0CH_3COOH=lamda_m^0CH_3COO^(-)+H^+`` alpha=lamda_m^0/lamda_x10^(-5)m^0=(4.95xx10^(-5))/(390.5xx^(-5))=0.0126`


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