1.

lambda_(m)^(@) for NaCl, HCl and CH_(3)COONa are 126.4,425.9 and "91.0 S cm"^(2)//"mol" respectively. Calculate lambda_(m)^(@)" for "CH_(3)COOH.

Answer»

SOLUTION :`lambda_(m_(CH_(3)COOH))^(@)=lambda_(CH_(3)COONA)^(@)+lambda_(HCl)^(@)-lambda_(NaCl)^(@)=91+425.4-126.4=390.5scm^(3)//mol`


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