lamda_(1) and lamda_(2) are used to illuminate the slits, beta_(1) and beta_(2) are the corresponding fringe widths. The wavelength lamda_(1) cm produce photoelectric effect when incident on a metal. But the wavelength lamda_(2) cannot produce photoelectric effect. the correct relation between beta_(1) and beta_(2) is :

lamda_(1) and lamda_(2) are used to illuminate the slits, beta_(1) and

1.	lamda_(1) and lamda_(2) are used to illuminate the slits, beta_(1) and beta_(2) are the corresponding fringe widths. The wavelength lamda_(1) cm produce photoelectric effect when incident on a metal. But the wavelength lamda_(2) cannot produce photoelectric effect. the correct relation between beta_(1) and beta_(2) is :
Answer» `beta_(1)ltbeta_(2)` `beta_(1)=beta_(2)` `beta_(1)gtbeta_(2)` `beta_(1)nebeta_(2)` Solution :Fring width `beta prop lambda`. AS GIVEN that `lambda_(1)` PRODUCED photo ELECTRIC EFFECT, so `lambda_(1) lt lambda_(2)` Hence, `beta_(1) lt beta_(2)`

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