lamda_m^0for NaCl,HCL and NaAc are 126.4,425.9and91.0Scm^2mol^(-1)resp – InterviewSolution

1.	lamda_m^0for NaCl,HCL and NaAc are 126.4,425.9and91.0Scm^2mol^(-1)respectively. Calculate^^_m^0for Hac.
Answer» SOLUTION :`^^_m^0(HA_C)=lamda_m^0(NAAC)+lamda_m^0(HCL)-lamda_m^0(NACL)` `=91+425.9-126.4=390.5Scm^2mol^(-1)`

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