1.

Lamda_(m(NH_(4)OH))^(@) is equal to_____

Answer»

`Lamda_(m(NH_(4)OH))^(@)+Lamda_(m(NH_(4)Cl))^(@)-Lamda_((HCl))^(@)`
`Lamda_(m(NH_(4)Cl))^(@)+Lamda_(m(NAOH))^(@)-Lamda_((NaCl))^(@)`
`Lamda_(m(NH_(4)Cl))^(@)+Lamda_(m(NaCl))^(@)-Lamda_((NaOH))^(@)`
`Lamda_(m(NaOH))^(@)+Lamda_(m(NaCl))^(@)-Lamda_((NH_(4)Cl))^(@)`

Solution :* `NH_(4)Cl` is strong electrolyte.
* According to KOHLRAUSCH LAW, limiting molar conductivity of electrolyte is the summation of positive and negative IONS, which are two individual ions PRESENT in the solution.


Discussion

No Comment Found

Related InterviewSolutions