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Laser light of wavelength 630 nm incident on a pair of slits produces an interference pattern in which the bright fringes are separated by 8.1 mm. a second light produces an interference pattern in which the fringes are separated by 7.2 mm. calculated the wavelength of the second light. |
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Answer» Solution :From RELATION `beta=(lamdaD)/(d)`, we find that, other factors remaining UNCHANGED `(beta.)/(beta)=(lamda.)/(lamda)` In present PROBLEM `beta=8.1`MM, `beta.=7.2mm and lamda=630mm` `THEREFORE lamda.=(beta.)/(beta)*lamda=(7.2mm)/(8.1mm)xx630nm=560nm` |
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