1.

Lattice energy of `NaCl_((s))` is `-788kJ mol^(-1)` and enthalpy of hydration is `-784kJ mol^(-1)`. Calculate the heat of solution of `NaCl_((s))`.A. `-4kJ`B. `4KJ`C. `-6KJ`D. `2KJ`

Answer» Correct Answer - B
heat of solution = L.E+H.E


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