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Least count of a vernier callipers is `0.01 cm` When the two jaws of the instrument touch each other the `5th` division of the vernier scale coincide with a main scale division and the zero of the vernier scale lies to the left of the zero of the main scale. Furthermore while measuring the diameter of a sphere, the zero markof the vernier scale lies between `2.4 cm` and `2.5 cm` and the `6th` vernier division coincides with a main scale division. Calculate the diameter of the sphere. |
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Answer» The instrument has a negative error, `e=(-5xx0.01)cm` or `e=-0.05 cm` Measured reading `=(2.4+6xx0.01)=2.46 cm` True reading = Measured reading `- e` `=2.46-(-0.05)` `=2.51 cm` Therefore, diameter of the sphere is `2.51` cm. |
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