\left. \begin{array} { l l l } { 6.02 \times 10 ^ { 18 } } & { ( 2 ) 6

1.	\left. \begin{array} { l l l } { 6.02 \times 10 ^ { 18 } } & { ( 2 ) 6.02 \times 10 ^ { 19 } } \\ { 3.0 \times 6.02 \times 10 ^ { 19 } } & { ( 4 ) 3.0 \times 6.02 \times 10 ^ { 18 } } \end{array} \right.
Answer» Molarity = moles/litre 0.1 = X . 1000/1 ( converted into ml) X = 10-4moles or 0.0001 moles and we know that Ba(NO3)2dissociates into Ba2++ 2NO3- the total no of ions = 3 in one mole so in 10-4moles = 3 . 10-4. 6.023.1023 18 * 10 ^ -19

\left. \begin{array} { l l l } { 6.02 \times 10 ^ { 18 } } & { ( 2 ) 6.02 \times 10 ^ { 19 } } \\ { 3.0 \times 6.02 \times 10 ^ { 19 } } & { ( 4 ) 3.0 \times 6.02 \times 10 ^ { 18 } } \end{array} \right.

Answer»

Molarity = moles/litre

0.1 = X . 1000/1 ( converted into ml)

X = 10-4moles or 0.0001 moles

and we know that Ba(NO3)2dissociates into Ba2++ 2NO3-

the total no of ions = 3 in one mole

so in 10-4moles =

3 . 10-4. 6.023.1023

18 * 10 ^ -19