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Length of a Rectangle is 8 cm less than twice its brearth of the rectangle is 56 m. Find the Length and breadth. Please solve the problem step-by-step in a paper and and take pic and post it here.​

Answer»

N:_________________________CORRECT QUESTION:Length of a Rectangle is 8 cm less than twice its brearth. Perimeter of the rectangle is 56 m. Find the Length and breadth.ANSWER:Length of the rectangle = 12M , Breadth of the rectangle = 24m.GIVEN:Length of a Rectangle is 8 cm less than twice its breadth.Perimeter of the rectangle = 56mTO FIND:Find the Length and breadth?SOLUTION:LET the breadth be x....(eq - 1)Length = (2x - 8)mPerimeter = 56m= 2 ( 2 x - 8 + x ) = 56m= 4x - 16 + 2x = 56m= 6x - 16 = 56mTranspose 16 towards the right.= 6x = 56 + 16m= 6x = 72M= x = 72/6m= x = 12mBreadth is 12m ( eq - 1 )Length = 2 × breadth = 2 × 12 = 24 ( Given, length = twice of its breadth. ) HENCE , Length of the rectangle = 12m , Breadth of the rectangle = 24m._________________________



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