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Let A = {1, 2, 3, 4} and R = {(1, 1), (2, 2), (3, 3), (4, 4), (1, 2), (1, 3), (3, 2)}. Show that R is reflexive and transitive but not symmetric. |
Answer» It is given that R = {(1, 1), (2, 2), (3, 3), (4, 4), (1, 2), (1, 3), (3, 2)} We know that (1, 1), (2, 2), (3, 3), (4, 4) ∈ R is reflexive. We know that (1, 2) ∈ R but (2, 1) ∈ R Hence, R is not symmetric. The same way (1, 2) ∈ R and (2, 3) ∈ R but (1, 3) ∈ R Hence, R is transitive. |
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