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Let A = {1, 2, 3} and R= {(1, 3), (3, 3)]. Findwhether the relation is (i) reflexive (ii) symmetrie(iii) transitive.The answer is only transitive.Answer it if you know the answer.How is it transitive? |
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Answer»
DETERMINE WHETHER the RELATION R in the set A={1,2,3,.. 13,14} defined as R={(x,y):3x−y=0}, is REFLEXIVE, symmetric and transitive. Answer Relation R on the set A={1,2,3,.,13,14} is defined as R={(x,y):3x−y=0} Let a∈A R is reflexive if (a,a)∈R if 3a−a=0 if 3a=a i.e. if 3=1 which is not true Thus, R is not reflexive (1) Let a,b∈A such that (a,b)∈R ⟹3a−b=0 ⟹3a=b This does not imply 3b=a i.e 3b−a=0 ∴(b,a) does not BELONG to R ∴ For a,b∈A, (a,b)∈R⟹(b,a) is not in R. Thus, R is not symmetric. . (2) Let a,b,c∈A such that (a,b),(b,c)∈R ⟹3a−b=0,3b−c=0 ⟹3a=b,3b=c ⟹3a= 3 c
⟹9a=c This does not imply (a,c)∈R ∴ For a,b,c∈A, (a,b),(b,c)∈R does not imply (a,c)∈R Hence, R is non-reflexive, non-symmetric and non-transitive. Please brainlest me the answer
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