1.

Let A = {1, 2}, B = {1, 2, 3, 4}, C = {5, 6} and D = {5, 6, 7, 8}. Verify that : i. A x C B x D ii. A x (B ∩ C) = (A x B) ∩ (A x C)

Answer»

Given : A = {1, 2}, B = {1, 2, 3, 4}, C = {5, 6} and D = {5, 6, 7, 8} 

(i) To prove : A × C ⊂ B × D 

LHS : A × C = {(1, 5), (1, 6), (2, 5), (2, 6)} 

RHS : B × D = {(1, 5), (1, 6), (1, 7), (1, 8), (2, 5), (2, 6), (2, 7), (2, 8), (3, 5), (3, 6), (3, 7), (3, 8), (4, 5), (4, 6), (4, 7), (4, 8)} 

Since, all elements of A × C is in B × D. 

∴We can A × C ⊂ B × D 

(ii) To prove : A × (B ∩ C) = (A × B) ∩ (A × C) 

LHS : (B ∩ C) = ∅ 

A × (B ∩ C) = ∅ 

RHS : (A × B) = {(1, 1), (1, 2), (1, 3), (1, 4), (2, 1), (2, 2), (2, 3), (2, 4)} 

(A × C) = {(1, 5), (1, 6), (2, 5), (2, 6)} 

Since, there is no common element between A × B and A × C 

⇒ (A × B) ∩ (A × C) = ∅ 

∴ LHS = RHS



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