1.

Let `A_1,A_2,A_3,….,A_m` be the arithmetic means between -2 and 1027 and `G_1,G_2,G_3,…., G_n` be the gemetric means between 1 and 1024 .The product of gerometric means is `2^(45)` and sum of arithmetic means is `1024 xx 171` The value of `Sigma_(r=1)^(n) G_r ` is

Answer» Correct Answer - C
`G_(1)G_(2)…G_(n)=(sqrt(1xx1024))^(n)=2^(5n)`
Given, `2^(5n)=2^(45)rArrn=9`
Hence, `r=(1024)^(1/(9+1))=2`
`rArrG_(1)=2,r=2`
`rArrG_(1)+G_(2)+..+G_(9)=(2xx(2^(9)-1))/(2-1)=1024-2=1022`


Discussion

No Comment Found