InterviewSolution
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InterviewSolution
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Let `A="{"-1,0,1")"a n df={(x , x^2): xA}dot`Show that `f: AvecA`is neitherone-one nor onto. |
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Answer» `f(x) = x^2` `:. f(-1) = 1, f(0) = 0, f(1) = 1` `=>f(-1) = f(1) = 1` It means, `f(x)` is not one-one. Now, range of `f = {0,1}` `A = {-1,0,1}` As, Range of `f != A`, `f` is not onto. `:. f: A->A` is neither one-one nor onto. |
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