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Let A = {2, 3, 4, 5, …, 17, 18}. Let ‘≃’ be the equivalence relation on A × A, cartesian product of A with itself, defined by (a, b) ≃ (c, d) if ad = bc. Then, the number of ordered pairs of the equivalence class of (3, 2) isA. 4B. 5C. 6D. 7 |
Answer» C. 6 Let (3,2) ≃ (x,y) ⇒ 3y = 2x This is possible in the cases: x = 3, y = 2 x = 6, y = 4 x= 9, y =6 x=12, y = 3 x=15, y = 10 x=18,y=12 Hence total pairs are 6. |
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