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Let `A=[{:(-5,-8,-7),(3,5,4),(2,3,3):}]` and `B=[{:(x),(y),(1):}]`. If `AB` is a scalar multiple of `B`, then the value of `x+y` isA. `-1`B. `-2`C. `1`D. `2` |
Answer» Correct Answer - B `(b)` `AB=lambdaB`, where `lambda` is non-zero scalar. `[{:(-5x-8y-7),(3x+5y+4),(2x+3y+3):}]=lambda[{:(x),(y),(2):}]` i.e., `{:(-5x-8y-7=lambdax),(3x+5y+4=lambday),(2x+3y+3=2lambda):}` Adding `0=lambda(x+y+2)` `lambda ne 0impliesx+y+2=0` `x+y=-2` |
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