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Let `A{:[(5,10),(10,20)]:},{:[(10,5),(15,10)]:}and={:[(-10,35),(25,-5)]:}`. Prove that AB = AC but `B!=C` |
Answer» `AB={:[(5,10),(10,20)]:}{:[(10,5),(15,10)]:}` `={:[((5)10+10(15),(5)5+(10)10),((10)10+(20)15,(10)5(20)10)]:}` `={:[(50+150,25+100),(100+300,50+200)]:}={:[(200,125),(400,250)]:}` `AC={:[(5,10),(10,20)]:}{:[(-10,35),(25,-5)]:}` `={:[(5(-10)+10(25),5(35)+10(-5)),(10(-10)+20(25),10(35)+20(-5))]:}` `={:[(-50+250,175-50),(-100+500,350-100)]:}` `={:[(200,125),(400,250)]:}`. Here AB=AC but `B!=C`. Hence Proved. |
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