InterviewSolution
Saved Bookmarks
| 1. |
Let ` A= [[5,5alpha,alpha],[0,alpha,5alpha],[0,0,5]]` .` If A^2 = 25,` then `alpha` equals to:A. `5^(2)`B. 1C. `1//5`D. 5 |
|
Answer» Correct Answer - C `A = [[5, 5alpha ,alpha ],[0,alpha,alpha5],[0,0,5]]rArr abs(AcdotA)= abs(A) abs(A)= (25alpha)^(2) = 25` `rArr alpha^(2) = 1/25` `rArr alpha = pm1/5` |
|