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| 1. |
Let `{:A=[(a,0,0),(0,a,0),(0,0,a)]:}`, then `A^n` is equal toA. `{:[(a^n,0,0),(0,a^n,0),(0,0,a)]:}`B. `{:[(a^n,0,0),(0,a,0),(0,0,a)]:}`C. `{:[(a^n,0,0),(0,a^n,0),(0,0,a^n)]:}`D. `{:[(na,0,0),(0,na,0),(0,0,na)]:}` |
| Answer» Correct Answer - C | |