Let a and b be real numbers such that sin sin a + b = 1/√2 and cos

1.	Let a and b be real numbers such that sin sin a + b = 1/√2 and cos a + cos b = √6/2 then the value of sin (a + b) is :(A) 1/2√2(B) 1/√3 (C) √3/2(D) 2/√3
Answer» Correct option (C) √3/2 Explanation: Given L : sin a + sin b = 1/√2 & M : cos a + cos b = √6/2, So L² + M² implies cos (a - b) = 0 while L M (using cos (a - b) = 0) gives sin (a + b) = √3/2

Let a and b be real numbers such that sin sin a + b = 1/√2 and cos a + cos b = √6/2 then the value of sin (a + b) is :(A) 1/2√2(B) 1/√3 (C) √3/2(D) 2/√3

Answer»

Correct option (C) √3/2

Explanation:

Given L : sin a + sin b = 1/√2 & M : cos a + cos b = √6/2,

So L² + M² implies cos (a - b) = 0

while L M (using cos (a - b) = 0)

gives sin (a + b) = √3/2

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Let a and b be real numbers such that sin sin a + b = 1/√2 and cos a + cos b = √6/2 then the value of sin (a + b) is :(A) 1/2√2(B) 1/√3 (C) √3/2(D) 2/√3

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