1.

Let A and B be two sets having 4 and 7 elements respectively. Then write the maximum number of elements that A⋃B can be.

Answer»

Here, 

n(A) = 4 and n(B) = 7 

Now, n(A⋃B) = n(A)+n(B) - n(A⋂B) 

= 4 + 7 - n(A⋂B) 

= 11 - n(A⋂B) 

So, 

n(A⋃B) is maximum whenever n(A⋂B) is minimum and it is possible only when A⋂B = ϕ 

Now, 

A⋂B = ϕ then min(n(A⋂B)) = 0. 

∴ min(n(A⋃B)) =11 - 0 =11



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