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Let A and B be two sets having 4 and 7 elements respectively. Then write the maximum number of elements that A⋃B can be. |
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Answer» Here, n(A) = 4 and n(B) = 7 Now, n(A⋃B) = n(A)+n(B) - n(A⋂B) = 4 + 7 - n(A⋂B) = 11 - n(A⋂B) So, n(A⋃B) is maximum whenever n(A⋂B) is minimum and it is possible only when A⋂B = ϕ Now, A⋂B = ϕ then min(n(A⋂B)) = 0. ∴ min(n(A⋃B)) =11 - 0 =11 |
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