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Let a,b,c,d be real numbers such that |a-b|=2, |b-c|=3, |c-d|=4 Then the sum of all possible values of |a-d|=A. 9B. 18C. 24D. 30 |
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Answer» Correct Answer - B `|a-b|=2 rArr a-b= pm 2` `|a-c|= 3 rArr b-c= pm 3` `|c-d|=4 rArr c-d = pm 4` Possible values of `a-d" are "pm 9, pm 5, pm 3, pm 1` `|a-d| =9, 5, 3, 1` Sum = 18. |
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