1.

Let A be a factor of 120. The number of positive integral solution of `x_1 x_2 x_3 = A `is :

Answer» `120=2*2*2*5*3`
`A=n_1n_2n_3`
A=1 times 2, 2=1
A=2 times 2, 2*2=2
A=3 times 2, 2*2*2=1
there are 4 possible ways
`2*2*2,2*2*3,2*2*5,2*3*5`


Discussion

No Comment Found