

InterviewSolution
Saved Bookmarks
1. |
Let A be a factor of 120. The number of positive integral solution of `x_1 x_2 x_3 = A `is : |
Answer» `120=2*2*2*5*3` `A=n_1n_2n_3` A=1 times 2, 2=1 A=2 times 2, 2*2=2 A=3 times 2, 2*2*2=1 there are 4 possible ways `2*2*2,2*2*3,2*2*5,2*3*5` |
|