1.

Let A be the set of all `3 xx 3` symmetric matrices all of whose entries are either 0 or 1. Five of these entries are 1 and four of them are 0. The number of matrices in A isA. 12B. 6C. 9D. 3

Answer» Correct Answer - A
A symmetric matrix is symmetric about its diagonal. So, there are even number of 1 and even number of 0 as off diagonal entries. Consequently, there can be either three 1 in the diagonal or one 1 and two zeros. Thus, we have the following cases:
CASE I When diagonal elements are 1,1,1.
In this case, we have
Number of symmetric matrices
= Number of arrangements of 1,0,0 as elements above the diagonal
`=(3!)/(2!)=3`
CASE II When diagonal elements are 1,0,0 ltbr. In this case, we have ltbRgt Number of symmetric matrices
=(Number of arrangements of 1,0,0 as entries above the diagonal)
`=(3!)/(2!)xx(3!)/(2!)=9`
`:. " Total number of matrices in " A=3+9=12`


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