Let a steel bar of length l, breadth b and depth d be loaded at the centre by a load W. Then the sag of bending of beam is (Y = Young's modulus of material of steel)

Let a steel bar of length l, breadth b and depth d be loaded at the ce

1.	Let a steel bar of length l, breadth b and depth d be loaded at the centre by a load W. Then the sag of bending of beam is (Y = Young's modulus of material of steel)
Answer» `(Wiota^3)/(2bd^3Y` `(Wiota^3)/(4bd^3Y` `(Wiota^2)/(2bd^3Y` `(Wiota^3)/(2bd^2Y` Solution : The sag of bending of BEAM is GIVEN by `delta=(WL^3)/(48Yl)` where, W = Load, L= Length =1, Y = Young's modulus \|= Moment of inertia = `(bd^3)/12` So, `delta=(Wl^3)/(48Ybd^3)xx12=(Wl^3)/(4Ybd^3)`

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Let a steel bar of length l, breadth b and depth d be loaded at the centre by a load W. Then the sag of bending of beam is (Y = Young's modulus of material of steel)

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