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Let `a,x,b` be in `A.P`, `a,y,b` be in `G.P` and `a,z,b` be in `H.P`. If `x=y+2` and `a=5z`, thenA. `y^(2)=xz`B. `x gt y gt z`C. `a=9`, `b=1`D. `a=1//4`, `b=9//4` |
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Answer» Correct Answer - A::B::C `(a,b,c)` `2x=a+b` `y^(2)=ab` `z=(2ab)/(a+b)` `x=y+2` and `a=5z` `z=(2y^(2))/(2x)` `impliesy^(2)=xz` `x=y+2` `:.(a+b)/(2)=sqrt(ab)+2`………`(i)` and `a=5((2ab))/(a+b)` `implies(a+b)=10b` `impliesa=9b` `:.` from `(i) (9b+b)/(2)=sqrt(9b^(2))+2` `implies5b=3b+2` `impliesb=1` So `a=9` `implies x gt y gt z` |
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