Let a1,a2…a3n be an arithmetic progression with a1=3 and a2=7. If a1+a2+…+a3n=1830, then what is the smallest positive integer m such that m(a1+a2+…+an)>1830?

Let a1,a2…a3n be an arithmetic progression with a1=3 and a2=7. If a

1.	Let a1,a2…a3n be an arithmetic progression with a1=3 and a2=7. If a1+a2+…+a3n=1830, then what is the smallest positive integer m such that m(a1+a2+…+an)>1830?
Answer» Let $a_{1}, a_{2} \dots a_{3 n}$ be an arithmetic progression with $a_{1} = 3$ and $a_{2} = 7$ . If $a_{1} + a_{2} + \dots + a_{3 n} = 1830$ , then what is the smallest positive integer m such that $m (a_{1} + a_{2} + \dots + a_{n}) > 1830$ ?

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Let a1,a2…a3n be an arithmetic progression with a1=3 and a2=7. If a1+a2+…+a3n=1830, then what is the smallest positive integer m such that m(a1+a2+…+an)&gt;1830?

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Let a1,a2…a3n be an arithmetic progression with a1=3 and a2=7. If a1+a2+…+a3n=1830, then what is the smallest positive integer m such that m(a1+a2+…+an)>1830?