InterviewSolution
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InterviewSolution
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Let `A3(0,4) and Bs(21,0) in R`. Let the perpendicular bisector of AB at M meet the y-axis at R. Then the locus of midpoint P of MR is `y=x^2 + 21`A. `x^(2) + y^(2) = (1)/(4) `B. `(y-2)^(2) - x^(2) = 4 `C. ` y + x^(2) = 2`D. `3x^(2) + y^(2) = 8` |
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Answer» Correct Answer - C The equation of MR is `y - 2 = (t)/(2) (x - t) implies tx - 2y + 4 -t^(2) = 0` It cuts y-axis at `( 0 , 2 - (t^(2))/(2))` Let P , (h , k) be the mid-point of MR . Then , ` h = (0 + t)/(2) , k = ( 2 - (t^(2))/(2) + 2)/(2)` `implies t = 2h , k = 2 - (t^(2))/(4) implies k = 2 - h^(2) implies h^(2) + k = 2` Hence , the locus of (h , k) is `x^(2) + y = 2`. |
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