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Let ABC be a triangle the position vectors of whose vertices are respectively `hati+2hatj+4hatk, -2hati+2hatj+hatk and 2hati+4hatj-3hatk`. Then the `/_ABC` is (A) isosceles (B) equilateral (C) righat angled (D) none of theseA. isoscelesB. equilateralC. right angledD. none of these |
Answer» Correct Answer - C `vec(BC) = vec(OC)-vec(OB) = 4hati+2hatj-4hatk` `" "vec(AB) = -3hati-3hatk, vec(AC) = hati=2hatj- 7hatk` `" "BC^(2) = 36, AB^(2) = 18, AC^(2)= 54 ` Cleary, `AC^(2) = BC^(2)m + AB^(2)` `therefore angleB= 90^(@)` |
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