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Let `alpha,beta`be the roots of the equation`(x-a)(x-b)=c ,c!=0`Then the roots of the equation `(x-alpha)(x-beta)+c=0`are`a ,c`(b) `b ,c``a ,b`(d) `a+c ,b+c` |
Answer» Since `alpha, beta` are the roots fo `(x-a)(x-b)=c` or `(x-a)(x-b)-c=0` Then `(x-a)(x-b)-c-(x-alpha)(x-beta)` `implies(x-alpha)(x-beta)+c=(x-a)(x-b)` Hence roots of `(x-alpha)(x-beta)+c=0` are a,b. |
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