Let and be two parallel lines and be a transversal. Let intersect in

1.	Let and be two parallel lines and be a transversal. Let intersect in L. suppose the bisector of ∠ALP intersect in R and the bisector of ∠PLB intersect in S. Prove that ∠LRS + ∠RSL = 90°
Answer» Let and be two parallel lines and be a transversal. Let intersect in L. suppose the bisector of ∠ALP intersect in R and the bisector of ∠PLB intersect in S. Prove that ∠LRS + ∠RSL = 90°

Let and be two parallel lines and be a transversal. Let intersect in L. suppose the bisector of ∠ALP intersect in R and the bisector of ∠PLB intersect in S. Prove that ∠LRS + ∠RSL = 90°

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Let and be two parallel lines and be a transversal. Let intersect in L. suppose the bisector of ∠ALP intersect in R and the bisector of ∠PLB intersect in S. Prove that ∠LRS + ∠RSL = 90°

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Let and be two parallel lines and be a transversal. Let intersect in L. suppose the bisector of ∠ALP intersect in R and the bisector of ∠PLB intersect in S. Prove that ∠LRS + ∠RSL = 90°

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