Let `arg(z_(k))=((2k+1)pi)/(n)` where `k=1,2,………n`. If `arg(z_(1),z_(2),z_(3),………….z_(n))=pi`, then `n` must be of form `(m in z)`A. `4m`B. `2m-1`C. `2m`D. None of these

Let `arg(z_(k))=((2k+1)pi)/(n)` where `k=1,2,………n`. If `arg(z_(1

1.	Let `arg(z_(k))=((2k+1)pi)/(n)` where `k=1,2,………n`. If `arg(z_(1),z_(2),z_(3),………….z_(n))=pi`, then `n` must be of form `(m in z)`A. `4m`B. `2m-1`C. `2m`D. None of these
Answer» Correct Answer - B `(b)` `arg(z_(1),z_(2),z_(3)……….z_(n))=pi` `impliesarg(z_(1))+arg(z_(2))+….+arg(z_(n))=pi+-2mpi`, `m in I` `implies (pi)/(n)[3+5+7+….+(2n+1)]=pi+-2mpi` `implies(pi)/(n)[(n)/(2)[6+2(n-1)]]=pi+-2mpi` `implies3+n-1=1+-2m` `impliesn=-1=1+-2m`

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Let `arg(z_(k))=((2k+1)pi)/(n)` where `k=1,2,………n`. If `arg(z_(1),z_(2),z_(3),………….z_(n))=pi`, then `n` must be of form `(m in z)`A. `4m`B. `2m-1`C. `2m`D. None of these

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