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Let ` cos (alpha+beta) = 4/5` and `sin(alpha-beta)=5/13 ` where `0 |
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Answer» Correct Answer - C `cos (alpha + beta )=(4)/(5)` `rArr tan (alpha + beta) = (3)/(4)` `" " sin (alpha - beta) = (5)/(13)` `rArr tan (alpha - beta) = (5)/(12)` ` therefore tan 2 alpha = tan (alpha + beta + alpha - beta)` ` " "= ((3)/(4)= (5)/(12))/(1-(3)/(4)(5)/(12)) = (56)/(33)` |
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