1.

Let ` cos (alpha+beta) = 4/5` and `sin(alpha-beta)=5/13 ` where `0

Answer» Correct Answer - C
`cos (alpha + beta )=(4)/(5)`
`rArr tan (alpha + beta) = (3)/(4)`
`" " sin (alpha - beta) = (5)/(13)`
`rArr tan (alpha - beta) = (5)/(12)`
` therefore tan 2 alpha = tan (alpha + beta + alpha - beta)`
` " "= ((3)/(4)= (5)/(12))/(1-(3)/(4)(5)/(12)) = (56)/(33)`


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