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Let E_(0) and B_(0) denote the amplitude of electric and magnetic filed of a plane electromagnetic wave in air. The magnitude of the average momentum transferred per unit area and per unit time to a totally abosorbing surface is |
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Answer» `1/2 epsi _(0) E_(0) ^(2)` `I = 1/2 epsi _(0) E_(0) ^(2)c =(1 B_(0) ^(2) c)/(mu_(0))` where `E_(0)=` electric field and c = speed of LIGHT. Now, momentum transfer per unit area per unit time, which is also called radiation PRESSURE. `I/A ((Deltap )/(DELTA t)) = I /c = ((1)/(2)epsi _(0) E_(0)^(2)c)/(c )` `I /c =1/2 epsi _(0) E_(0)^(2)` [where, `Deltap,=` momentum transferred, `DELTAT=` time and A = area.] |
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